PCB Trace Width Calculator

A
°C
External width
1.37 mm (53.82 mil)
Internal width
3.56 mm (140.01 mil)

How to Use the PCB Trace Width Calculator

Printed circuit board traces carry current like miniature wires, but flat copper foils heat differently than round conductors. Too narrow a trace for the load current causes excessive temperature rise, delamination, and voltage drop that disrupts sensitive analog circuits. PCB layout engineers use IPC-2221-style curves (or the simplified formulas derived from them) to pick minimum trace width before routing power nets.

The underlying relationship estimates required cross-sectional area based on current and allowed temperature rise, then converts area to width given copper thickness:

Area (mil²) = (I / (k × ΔTb))1/c

Width (mil) = Area / Thickness (mil)

Where I is current in amperes, ΔT is temperature rise in °C above ambient, k is 0.048 for external layers or 0.024 for internal (less heat dissipation), b = 0.44, and c = 0.725. Copper thickness in oz/ft² converts to mils: 1 oz ≈ 1.378 mil.

External layers cool better than buried inner layers — the same current needs wider internal traces. Standard fab offerings are 1 oz (35 µm) and 2 oz (70 µm) copper; heavy copper (3–6 oz) suits power modules. Always confirm with your fabricator's capability and require wider traces for long runs with voltage-drop budgets.

Worked example: A 3 A power rail on 1 oz external copper, allowing 10°C rise: area ≈ (3/(0.048×100.44))1/0.725 ≈ 42 mil². Width = 42/1.378 ≈ 30.5 mil (0.77 mm). For 10 A with 20°C rise: area ≈ 320 mil² → width ≈ 232 mil (5.9 mm) — why high-current PCBs use planes or bus bars. Doubling to 2 oz copper halves required width for the same rise.

Cross-check long power traces with the wire size calculator mindset — milliohms per square sheet resistance adds up over centimeters.

Trace width guidelines (1 oz external, 10°C rise)

CurrentWidth (mil)Width (mm)Note
0.5 A100.25Signal/power default
1 A150.38USB VBUS
2 A240.61Small DC-DC output
3 A310.77Motor driver
5 A481.22Use plane preferred
10 A952.41Heavy copper advised

Frequently asked questions

1 oz/ft² is the default for most prototypes. Enter 2 oz for power boards or when the fab offers heavy copper upgrades.

Inner layers dissipate heat through laminate on both sides with less convection, so they run hotter unless widened.

No — it targets temperature rise. Long traces also need voltage-drop checks; use wider copper or pours than the minimum thermal width.

Related tools

Related conversions